Question

2X2 - 6X + k = 0 या वर्गसमीकरणाची मुळे वास्तव व समान आहेत तर k ची किंमत काढा .​

Answer 1

Step-by-step explanation:

(3x2−2x−1)(2x2+x−5)=x4+3x3−15x2−4x3−2x2+10x−2x2−1+5=6x4−x3−19x2+9x+5

Answer 2

Answer:

Hey!! Ur answer:

2x2−6x+k=0 is given by:

⇒(−6)2−4(2)(k)=0

⇒36−8k=0

From the above expression determining the value of k, as given below:

⇒k=368

∴k=9/2

Hence the value of k is 9/2.

Step-by-step explanation:

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