2x² +8x + 8 = 0 find the zeroes of polynomial
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the zero of the polynomial is -2 because if we substitute x as -2 we get the value of the polymial as zero that is,
2(-2)^2 +8(-2)+8
8-16+8
=0
2(-2)^2 +8(-2)+8
8-16+8
=0
Aayushsingh1:
no
i forgot to put the minus there so
Answered by
3
8x can be written as 4x+4x,
Now the equation would be 2x²+4x+4x+8 = 0,
take 2x common in first two terms and 4 in last two terms,
=>2x(x+2)+4(x+2) = 0, Now take (x+2) common,
=> (x+2)*(2x+4) = 0,
=> Either x+2 = 0 or 2x+4 = 0,
=> Either x = -2 or x = -4/2 = -2, But both are same, So there is only 1 zero of the polynomial but two roots,
=> The zero of the polynomial is -2,
Hope you understand, Have a great day !!
Now the equation would be 2x²+4x+4x+8 = 0,
take 2x common in first two terms and 4 in last two terms,
=>2x(x+2)+4(x+2) = 0, Now take (x+2) common,
=> (x+2)*(2x+4) = 0,
=> Either x+2 = 0 or 2x+4 = 0,
=> Either x = -2 or x = -4/2 = -2, But both are same, So there is only 1 zero of the polynomial but two roots,
=> The zero of the polynomial is -2,
Hope you understand, Have a great day !!
right
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