2x²- x + 1/8 find the roots
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Answered by
2
Answer:
2x²-x+(1/8)=0 ,[L.C.M=8]
16x²-8x+1=0
16x²-4x-4x+1=0
4x[4x-1]-1[4x-1]=0
[4x-1][4x-1]=0
[4x-1]²=0
Take √
4x-1=0
4x=1
X=1/4
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Answered by
0
Answer:
2x^2-x+1/8=0
LCM this equation
16x^2-8x+1=0
(break 8x)
16x^2-4x-4x+1=0
(16x^2-4x)-(4x+1)
4x(4x-1)-1(4x-1)
(4x-1)(4x-1)
x=1/4, 1/4
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