Math, asked by pawansahu9399, 7 months ago

2x²- x + 1/8 find the roots​

Answers

Answered by gboy8
2

Answer:

2x²-x+(1/8)=0 ,[L.C.M=8]

16x²-8x+1=0

16x²-4x-4x+1=0

4x[4x-1]-1[4x-1]=0

[4x-1][4x-1]=0

[4x-1]²=0

Take √

4x-1=0

4x=1

X=1/4

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Answered by gargr3094
0

Answer:

2x^2-x+1/8=0

LCM this equation

16x^2-8x+1=0

(break 8x)

16x^2-4x-4x+1=0

(16x^2-4x)-(4x+1)

4x(4x-1)-1(4x-1)

(4x-1)(4x-1)

x=1/4, 1/4

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