Question

(
2x3+x2–2x-1) = (x+1)​

Answer 1

Step-by-step explanation:

($2x^3+x^2-2x-1$) = (x+1)

⇒​$\frac{2x^3+x^2-2x-1}{x+1} =1$

⇒$2x^2-x-1=1$

⇒$2x^2-x-2=0$

$x=\frac{1±\sqrt{17} }{4}$