2xsqare +kx +3=0 find the value of K
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✓ Given : 2x² + kx + 3 = 0
For equal roots :
b² - 4ac = 0
⇒ (k)² - 4.(2).(3) = 0
⇒ k² - 24 = 0
⇒ k² = 24
⇒ k = ± √ 24 ⇒ k = ± 2√6
Cheers!
✓ Given : 2x² + kx + 3 = 0
For equal roots :
b² - 4ac = 0
⇒ (k)² - 4.(2).(3) = 0
⇒ k² - 24 = 0
⇒ k² = 24
⇒ k = ± √ 24 ⇒ k = ± 2√6
Cheers!
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