3✓2+2✓3 by 5✓2-4✓3=a-b✓6 . Find a and b
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Answer:
Step-by-step explanation:
3√2+2√3/5√2-4√3=a-b√6
By conjugating the term,
3√2+2√3(5√2+4√3)/5√2-4√3(5√2+4√3)=a-b√6
3√2(5√2+4√3)+2√3(5√2+4√3)/
5√2-4√3(5√2+4√3)=a-b√6
15*2+12*√6+10*√6+8*3/
(5√2)^2-(4√3)^2(by identity)=a-b√6
30+12√6+10√6+24/25*2-16*3=a-b√6
54+22√6/50-48=a-b√6
2(27+11√6)/2=a-b√6
27+11√6=a-b√6
a=27;b=11
*identity used*=(a+b)(a-b)=a^2-b^2
HOPE IT HELPED YOU PLS MARK AS BRAINLIEST
samalok09:
in the last step by comparing the coefficients on both sides b would come as -11 as on RHS it is a-b root over 6
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