Math, asked by guddandolly115, 1 year ago

3/2x-5/3y=-2;x/3+y/2=13/6 solve by substitution method

Answers

Answered by Nani11111111
4
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Answered by Anonymous
21

\Large{\underline{\underline{\bf{Solution:-}}}}

\rm{ \frac{3x}{2}  -  \frac{5y}{3}   =  - 2.......(i)}

\rm{\frac{x}{3}  +  \frac{y}{2}  =  \frac{13}{6}.......(ii)}

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{\bold{\underline{\underline{from\: equation\: (i), \: we \: obtain}}}}

\rm{9x-10y = -12}

\rm{ x =  \frac{ - 12 + 10y}{9} ......(iii)}

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{\bold{\underline{\underline{Substituting\: this\: value\: in \: equation\: (ii), \: we \: obtain}}}}

\rm{\frac{ \frac{ - 12 + 10y}{9} }{3}   +  \frac{y}{2}  =  \frac{13}{6}}

\rm{\frac{ - 12 + 10y}{27}  +  \frac{y}{2}  =  \frac{13}{6} }

\rm{ \frac{ - 24 + 20y + 27y}{54}  =  \frac{13}{6} }

\rm{ 47y = 117 + 24}

\rm{ 47y = 141}

\rm{y = 3.......(iv)}

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{\bold{\underline{\underline{Substituting\: this\: value\: in \: equation\: (iii), \: we \: obtain}}}}

\rm{x =  \frac{ - 12 + 10 \times 3}{9} }

\rm{x =  \frac{18}{9} }

\rm{x=2}

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{\rm{\boxed{\boxed{x=2}}}}

{\rm{\boxed{\boxed{y=3}}}}

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\Large{\underline{\underline{\bf{Thanks}}}}

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