Physics, asked by subhenduroy53, 6 months ago

3.91. The area of plates of the parallel plate
capacitor, to obtain capacity of 0.3 x
10- uF if they are separated by a dis-
tance of 10 mm and a dielectric between
them of permittivity = 2.5, will be

Answers

Answered by kanchikhurana
1

Answer:

Apply this formula C

eq

=

d−t

1

(1−

k

1

1

)−t

2

(1−

k

2

1

)

ϵ

0

A

where t

1

=6,t

2

=4,k

1

=10,k

2

=5,d=10mm

C

eq

=

10−6(1−

10

1

)−4(1−

5

1

)

ϵ

0

A

=

7

5

×10

−3

ϵ

0

A

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