Question

3 a Chinua reacts 37 g of magnesium with 150 g of sulfuric acid.
What will be the total mass of the products of this reaction?
b If Chinua starts with 10g of magnesium, how much magnesium
will be present in the magnesium sulfate?

Answer 1

Answer:

Solution: - (C) 30 As we know that, No. of moles = wt.mol. wt. Now,Wt. of Mg = 6 g Mol. wt. of Mg = 24 g No. of moles of Mg in 6 g = 624 = 0.25 moles