3.
A life insurance agent found the following data about distribution of ages of 100 policy
holders. Calculate the median age. [Policies are given only to persons having age 18
years onwards but less than 60 years.]
Below Below Below Below Below Below Below Below Below
Age
(in years)
20
25
30
35
45
50
55
60
Number of
2
6
24
45
78
89
92
98
100
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Class intervalFrequencyCumulative frequency 15−202 2 20−254 6 25−3018 24 30−3521 45 35−4033 78 40−4511 89 45−503 92 50−556 98 55−602 100 ⇒ N=100 then, 2N=50
The cumulative frequency just greater then 50 is 78.
∴ Median class =35−40
Here, l=35,h=5,f=33,cf=45
Median=l+f2N−cf×h
⇒ Median=35+3350−45×5
⇒ Median=35+3325=35.76
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