Math, asked by Edevesh, 3 months ago


3. A rectangular floor of dimensions 8.4 mx 54 m is to be tiled with right-triangular marble pieces,with base 40 cm and height 30 cm. How many marble pieces will be required to cover the floor?​

Answers

Answered by smosan75
19

\large{\red{\mathcal{QUESTION:–}}}</p><p>

A rectangular floor of dimensions 8.4 mx 54 m is to be tiled with right-triangular marble pieces,with base 40 cm and height 30 cm. How many marble pieces will be required to cover the floor?

\large{\red{\mathcal{GIVEN:–}}}

DIMENSIONS OF THE FLOOR=8.4m × 54m=840cm × 5400cm

BASE OF TRIANGULAR TILE=40cm

HEIGHT OF TRANGULAR TILE=30cm

\large{\red{\mathcal{FIND:–}}}

How many marble pieces will be required to cover the floor?

\large{\red{\mathcal{SOLUTION:–}}}

AREA OF THE FLOOR=LENGTH × BRADTH

(840×5400)cm²=4,536,000cm²

AREA OF TILE=1/2 × BASE × HEIGHT

(1/2 × 40 ×30)cm²=600cm²

therefore, number of tiles needed=4536000/600=7,560

\large{\red{\mathcal{ANSWER:–}}}

7,560 TILES

Similar questions