3. A ring contain 1.2g of diamond (allotropic form of C) calculate the number of carbon atoms in the ring.
NA/10
NA
NA2
1.2 NA
Answers
Answer:
When we will have to find no. of particles(atoms, ions or molecules) in something then we apply following formula:
moles(n)=no. of particles(atoms, ions or molecules)/NA(Avogadro’s no)
In case diamond which is basically carbon, first of all we find its no. of moles by following formula:
moles(n)= Given mass/molar mass
So, moles(n)=10 g/12 g/mol
moles(n)=0.8333
Now with the help of these calculated moles, we can find no. of carbon atoms in 10 g of diamonds as:
no. of atoms= moles(n) x Avogadro’s no(NA)
no. of atoms= (0.8333) x (6.02 x 10^23)
no. of carbon atoms= 5.016 x 10^23
Explanation:
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Answer:
NA/10
Explanation:
diamond is basically carbon so .
the mass is given which is 1.2
molar mass of the carbon is 12
so mole 1.2/12=0.1 moles
no of mole multiply with NA which is,
0.1 multiply 6.02 10^23=6.02 10^22