Question

The ratio of length and breath of a varandha is 3:2 and its perimeter is 40 m. Find the length ,breath ,area . Hense find the cost pf flooring at Rs 12.50 per m square​

Answer 1

Answer:

$\huge\underline\bold{Given-}$

Length = 3x

Breadth= 2x

Perimeter = 40m

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$\huge\underline\bold{To\:Find -}$

↬Dimensions.

↬Area.

↬Cost of flooring.

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$\huge\underline\bold{Solution -}$

➼The first step is to find the dimensions of the antispated figure.

$\color{black}\boxed{\colorbox{saffron}{Perimeter-2(length+breadth) }}$

40=2(3x+2x)

40= 2×5x

40=10x

$\frac{40}{10}$=x

4=x

So, dimensions are -

Length= 3x=3×4= 12m

Breadth=2x=2×4=8m

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➼Now, as we know the dimensions of the figure, we will now find area.

$\color{black}\boxed{\colorbox{saffron}{Area - length×breadth}}$

$= 12 \times 8 \\ \\ = {96m}^{2}$

So,

Area = $\bold{96m}^{2}$

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➼Finally, we will find the cost of flooring the varanda.

96×12

= ₹1152

So,

Cost of flooring = ₹1152

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$\huge\underline\bold{Required\:Answer-}$

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↬Length=12m, Breadth=8m

↬Area=${96m}^{2}$

↬Cost of flooring = ₹1152

Answer 2

Answer:

Given :

• Ratio Of length and breadth - 3 : 2

• Perimeter - 40 m

• Flooring at m per square - 12.50

To Find :

• Area Of Rectangle

• Length

• Breadth

Formula To Find :

${\underline{\boxed{\bf{Area \: of \: Rectangle \: = l \: \times b }}}}$

${\underline{\boxed{\bf{Perimetre \: of \: Rectangle \: = 2 \times( l + b) \: }}}}$

Where,

• l = length

• b = breadth

Solution :

Let take 3x and 2x are breadth and length :

$\sf \to \: Perimetre \: of \: Rect. \: = 2 \times (l + b)$

$\to\sf \: 2 \times (3x + 2x) = 40$

$\sf\to \: 2 \times 3x + 2 \times 2x = 40$

$\sf \to \: 6x + 4x = 40$

$\sf \to \: 10x = 40$

$\sf \to \: x = \dfrac{40}{10}$

$\bf \to \: x = 4$

Length :

$\sf \to \: 3x = 3 \times 4 = 12$

Breadth :

$\sf \to \: 2x = 2 \times 4 = 8$

$\therefore \sf Length \: and \: Breadth \: of \: rect. \: = 12 \: and \: 8 \: m$

Area Of Rectangle :

$\sf \to \: Area \: = l \times b$

$\sf\to \: 12 \times 8$

$\bf \to \: 96 \: {m}^{2}$

$\therefore \sf \: Area \: of \: Rect. \: = 96 \: {m}^{2}$

Cost of Flooring :

$\bf \: Area \times Cost \: of \: ₹ \: per \: square \: m$

$\sf \to \: 96 \times 12.50$

$\to \bf \: 1200$

$\therefore \sf Cost \: of \: flooring \: = ₹ 1200$