3 bags and 4 paint cost together rupees 254 whereas 4 bags and 3 pens cost together rupees 324 find the cost of 1 bag and 1 pen
Answers
UR ANSWER IS:
3 BAGS + 4 paint = ₹254
4 bags+3 pens=₹ 324
Let’s Bags = b and Pens = p
4b+3p=₹324
3b+4p=₹254
Subtracting (4b+3p) from (3b+4p)
7p=56
P = 8
Putting p = 8 in equation 1 we get b = 75
Cost of 1 pen= ₹8
Cost of 1 bag=₹75
HOPE THIS MAKES UR DAY BETTER!!
Step-by-step explanation:
●Given:
3 bags + 4 pens = rs. 254
4 bags + 3 pens = rs. 324
☆ Solution
Let the cost of 1 bag be x
Let the cost of 1 pen be y
Now we can form an equation.
3x + 4y = 254
4x + 3y = 324
We will multiply eq 1 by 4 and eq 2 by 3 to cancel out one variable, i.e x
(3x + 4y = 254) 4
(4x + 3y = 324) 3
= 12x + 16y = 1016
12x + 9y = 972
7y = 44
y = 44/7 or rs. 6.2857
Now we will put the value of y in eq 1 to get the value of x.
3x + 4 (44/7) = 254
= 3x + 176/7 = 254
= 21x + 176/7 = 254 (taking 7 as L.C.M)
= 21x + 176 = 254 ×7
= 21x + 176 = 1778
= 21x = 1778 - 176.
= 21x = 1602
= x = 1602/21
x = 534/7 or rs. 76.2857
So, cost of 1 bag = rs.76.2857 and 1 pen = rs. 6.2857
■ Cross Checking
3 bags + 4 pens = rs. 254
3× 534/7 + 4 × 44/7 = 254
= 1602/7 + 176/7= 254
= 1778/7 = 254 (taking 7 as L.C.M)
= 254= 254
hence proved.