Question

3. Calculate average speed of oxygen at 27°C.
1) 645.42 ms
2) 545.42 ms
3) 445.42 ms
4) 745.42 ms​

Answer 1

Explanation:

ANSWER

27

∘

C=300 K

Root mean square speed =

M

3RT

R=8.314×10

7

erg K

−1

mol

−1

;M=32 g mol

−1

;T=300 K

Substituting the values,

=

32

3×8.314×10

7

×300

=483.56 cm/sec

=483.56 m/sec

Average speed =

πM

8RT

=

22×32

8×8.314×10

7

×300×7

=445.42 cm/sec

=445.42 m/sec

Most probable speed =

M

2×R×T

=

32

2×8.314×10

7

×300

=39482 cm/sec

=394.83 m/sec.

Answer 2

Answer : 3). average speed of O2 at 27°C is 445.42 ms