Question

3 conductors of resistances 1 ohm and 2 ohm and 3 ohm are connected. in series
in parallel calculate the effective resistance of each combination

Answer 1

Let the equivalent Resistance be 'R'

If 3 conductors are connected in series, then the effective resistance = 1+2+3=6 ohm

If connected in parallel = 1÷1+1÷2+1÷3= 6+3+2÷6=11÷6 ohm

Answer 2

Answer:

Explanation:

Series and Parallel:

A series circuit has the same amount of current flowing through all of its components. In parallel circuits, on the other hand, the components are connected in parallel, causing the circuit to split the current flow.

Let R1 = 1Ω, R2 = 2Ω, R3 = 3Ω

When the three resistors are connected in parallel…

R_effecive = 1/(1/R1 + 1/R2 + 1/R3) Ω

                  = 1/(1/1 + 1/2 + 1/3) Ω

                  = 1/( (6 + 3 + 2)/6 ) Ω

                  = 1/(11/6) Ω

                  = 6/11 Ω

                  = 0.54 Ω

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