3 different numbers are chosen such that when each of the numbers is added to the average of the remaining 2, it given 65, 69 and 76 as a result. what is the average of the 3 original number?
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let 3 numbers be a , b and c then
according to the question
(a+b)/2 + c = 65
(c+b)/2 + a = 69
(a+c)/2 + b = 76
by adding 3 equations
a+b+c = 140(by solving)
so avarage is 140/3 = 46.6
according to the question
(a+b)/2 + c = 65
(c+b)/2 + a = 69
(a+c)/2 + b = 76
by adding 3 equations
a+b+c = 140(by solving)
so avarage is 140/3 = 46.6
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