Question

3. Find m if (m-12)x2 + 2(m-12)x + 2 = 0 has real and equal roots.​

Answer 1

Step-by-step explanation:

the value of m is 14 and 12

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Answer 2

Answer:

m = 14

Step-by-step explanation:

The relationship between roots and coefficients of quadratic equation

ax² + bx + c = 0

is

$x_{1}$ + $x_{2}$ = - $\frac{b}{a}$

$x_{1}$ × $x_{2}$ = $\frac{c}{a}$

~~~~~~~~~~~~~~~

In given equation: a = m - 12, b = 2(m - 12), c = 2 and roots are equal.

2x = - $\frac{2(m-12)}{m-12}$ = - 2 (m ≠ 12) ===> x = - 1

Substitute "x" by (- 1) in given equation

(m - 12)(- 1)² + 2(m - 12)(- 1) + 2 = 0

m - 12 - 2m + 24 + 2 = 0

m = 14