Question

3. Find the area of the trapezium whose
parallel sides are 45 cm and 37 cm and the
distance between them is 20 cm.​

Answer 1

$\huge\boxed{\boxed{\blue{\sf{Solution-}}}}$

$\boxed{\sf{\purple{Area \:of \:Trapezium=\frac{1}{2}×Sum of parallel sides ×Height }}}$

Given :-

AB=45cm,

DC=37cm

DE=20cm

$\sf{Area \:of \:Trapezium=\frac{1}{2}×DE(AB+DC)}\\ \sf\implies Area \:of \:trapezium=\frac{1}{2}×20(45+37)\\ \sf\implies Area =\frac{1}{2}×20×82\\ \sf\implies Area=\frac{1}{2}×1640\\ \sf\implies Area=\frac{1640}{2}\\ \sf\implies Area\:of\: trapezium=820cm{}^{2}$

Check The attachment Also !

$\boxed{\sf{\blue{Area \:of \:Trapezium=820cm{}^{2} }}}$