Math, asked by ronishshrestha85, 5 months ago

3. Find the cube of:
i. (2a + 3b) ii. (3x - 4y) iii. (4 + 5m) iv. (p + q)

Answers

Answered by swapna8622
1

Answer:

(2a + 3b) {}^{3}  = 8a {}^{3}  + 27b {}^{3}  + 36a {}^{2} b + 54ab {}^{2}

(3x + 4y) {?}^{3}  = 27x {}^{3}  - 64y {?}^{3}  - 108x {}^{2} y + 144xy {}^{2}

(4 + 5m) {}^{3}  = 64 + 125m {}^{ 3}  + 240m + 300m {}^{2}

(p + q) {}^{3} = p { }^{3}  + q {}^{3}  + 3p {}^{2} q + 3pq {}^{2}

Answered by deeshu1244
0

Answer:

(2a + 3b) {}^{3} = 8a {}^{3} + 27b {}^{3} + 36a {}^{2} b + 54ab {}^{2}(2a+3b)

3

=8a

3

+27b

3

+36a

2

b+54ab

2

(3x + 4y) {?}^{3} = 27x {}^{3} - 64y {?}^{3} - 108x {}^{2} y + 144xy {}^{2}(3x+4y)?

3

=27x

3

−64y?

3

−108x

2

y+144xy

2

(4 + 5m) {}^{3} = 64 + 125m {}^{ 3} + 240m + 300m {}^{2}(4+5m)

3

=64+125m

3

+240m+300m

2

(p + q) {}^{3} = p { }^{3} + q {}^{3} + 3p {}^{2} q + 3pq {}^{2}(p+q)

3

=p

3

+q

3

+3p

2

q+3pq

2

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