Question

3 forces each of 2N can be represented by 3 sides of a quadrilateral in the order then the resultant of these forces. A.6N B.4N. C.2√2N. D 2N​

Answer 1

Answer:

Let the two vectors be A and B, and their resultant be R.

Let the angle between A and B be θ

A=2N

B=3N

R=4N

Now R2=A2+B2+2ABcosθ

So,42=22+32+2×3×4cosθ

So, 16=4+9+24cosθ

So, 16=13+24cosθ

So, 3=24cosθ

So, 243=cosθ

So, cosθ=1/8

So, θ=cos−1(1/8)