Math, asked by adityardiwan, 1 year ago

3 friends were asked to eat a dish cost 20 per plate,they contributed rs20 each, when the owner of the shop saw that those 3 persons were their regular customers, he discounted rs10 and said to the waiter,go and give this 10rs to those persons, the waiter expended rs4 and bought cigarettes, and gave rs 6 to those 3 friends, friends distributed rs2 each, according to this they paid rs 18 each, on multiplying rs18 by 3 we get rs54,and on adding rs4 for the waiter's cigarettes, total cost is rs58,where is rs2 gone,since they gave rs 60

Answers

Answered by chbilalakbar
0

Answer

There is no issue of any 2 Rs is present in question.Its actually fault of calculation

Step-by-step explanation:

Please try to understand,cool down and try the estimate as I have done

Let

They altogether pay = 60

number of friends = 3

discount given by owner of shop = 10

NOW AT This stage we have to divide 50 into all friend that is

50 / 3 =16.6666......

So

one friend spend on dish = 16.6666...

The tip of waiter = 4

So Dividing 4 by 3 we get

4/3 = 1.33333.....

So

one friend spend for tip = 1.3333.....

Thus

Total spend by one friend = spend on dash + tip given to waiter

                                            = 16.6666.....  +  1.333....

                                            = 18

(Because every friend have 2 Rs as Reminder)

So

Total spend by all friends = 3 × spend by one = 3 × 18

                                                                            = 54

NOW

Since every friend have 2 rupees so altogether 6 rupees

and

54 + 6 = 60

60 rupees  completed

NOW tell me where is issue of 2 Rupess gone.Actually its fault of  calculation.

When you said every friend spend 18 Rs its actually contain tips rupees but you add 4 in 54 to get 58 and create the issue of  2 Rs.

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