Question

3) If sec(theta+36)=cosec theta, find theta is equals to

Answer 1

$\sec( \theta + 36 \degree) = \cosec( \theta) \\ \\ => \sec( \theta + 36 \degree) = \sec(90 - \theta ) \\ \\ = > \theta + 36 = 90 - \theta \\ \\ = > 2 \theta = 54 \\ \\ = > \theta = 27 \degree$

Answer 2

Heya !!



Sec ( ¢ + 36 ) = Cosec ¢






Sec ( ¢ + 36 ) = Cosec(90- ¢ )





¢ + 36 = 90 - ¢




¢ + ¢ = 90 - 36



2¢ = 54



¢ = 54/2



¢ = 27.