Chemistry, asked by armanalfzhfayrzfhai7, 6 months ago

3. In Fig. 6.41, if AB || DE, ZBAC=35° and CDE=53°, find ZDCE.


А
PA 1135
35
620
549
110°
Y
Z
D532
T
о Q
R
Fig. 6.39
Fig. 6.40
Fig. 6
4. In Fig. 6.42, if lines PQ and RS intersect at point T, such that Z PRT=40°.2
and ZTSQ = 75°, find ZSQT.​

Answers

Answered by sonkarrekha652
3

Answer:

∠DCE = 92°

Step-by-step:

∠AED = ∠BAC ..............(alternate interior angles)

⇒∠AED = 35°

⇒∠CED = 35°

InΔDEC

∠CDE + ∠DCE + ∠CED = 180° ...........(by angle sum property)

53° + ∠DCE + 35° = 180°

∠DCE + 88° = 180°

∠DCE = 180° − 88°

∠DCE = 92°

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