Question

Upon signal of starting the race an athlete starts from rest with a constant acceleration of 8m/s2. At the same time a cyclist travelling with a constant speed of 72km/h passes the athlete. How far beyond the starting point will the athlete overtake the cyclist and what will be the speed of the athlete at the time he overtakes the cyclist?
A).100m, 40m/s
B). 110m, 50m/s
C). 120m, 60m/s
D). 130m, 70m/s
E). 140m, 80m/s
Someone pls tell the correct answer with explanation correct answer will get brainliest!

Answer 1

Answer:

100m.and 40m/s is the right answer

Explanation:

for athlete:

d=initial velocity*time+1/2acceleration*time2

d=0+1/2(8)(t)^2.

d=4t^2......(i)

for cyclist:

d=velocity*time

d=72km/h or 20m/s *t

d=20t.....(ii)

using i and ii:

d=d

4t^2=20t

t=5s

putting value of time in equation i:

d=4t^2

d=4(25)

d=100m

for velocity:

vf=vi+at

vf=0+(8)(5)

vf=40m/s