_/3 is a
zeo of a polynomial P(x)
find the value
of
_/3.p (_/3)
Answers
Answered by
0
Answer:
p(root 3) : root 3x root 3
p(root,3) -3
Answered by
0
Answer:
Now, we are having a polynomial \[2{{x}^{2}}+x+k\] we are asked to find k such that 3 is zero of the polynomial. Hence, 3 is a zero, so we get k as – 21. As we get P(3) = 0, so k = – 21 is the correct solution.
Similar questions