Question

see the attachment nd plz solve it....​

nd don't spam otherwise your answer will be reported..​

Answer 1

Step-by-step explanation:

$\begin{gathered} \sf \: cos^2x+cos^2(x+\frac{\pi}{3})+cos^2(x-\frac{\pi}{3}) \\ \sf \: \to cos^2x+(cos(x+\frac{\pi}{3})+cos(x-\frac{\pi}{3}))^2-2\times cos(x+\frac{\pi}{3})cos(x-\frac{\pi}{3}) \\ \sf \: \to cos^2x+(2cosx\times cos\frac{\pi}{3})^2 - (cos2x+cos\frac{2\pi}{3})\\ \sf \: \to cos^2x+(2cosx\times \frac{1}{2})^2 - cos2x-cos\frac{2\pi}{3}\\\to \sf \: cos^2x+cos^2x-cos2x-(\frac{-1}{2})\\ \sf \: \to 2cos^2x-cos2x+\frac{1}{2}\\ \sf\to 1+\frac{1}{2}\\ \sf\to \pink{ \frac{3}{2}}\end{gathered}$

Answer 2

Question:-

Attachment.

Correct answer:-

cos

2

x+cos

2

(x+

3

π

)+cos

2

(x−

3

π

)

→cos

2

x+(cos(x+

3

π

)+cos(x−

3

π

))

2

−2×cos(x+

3

π

)cos(x−

3

π

)

→cos

2

x+(2cosx×cos

3

π

)

2

−(cos2x+cos

3

2π

)

→cos

2

x+(2cosx×

2

1

)

2

−cos2x−cos

3

2π

→cos

2

x+cos

2

x−cos2x−(

2

−1

)

→2cos

2

x−cos2x+

2

1

→1+

2

1

→

2

3

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