Question

(3) Jerrin applied a force of 80 N on a simple machine through a distance of 1 m and was able to pull a load of 120 N through a distance of 40 cm. Find the efficiency of the machine.​

Answer 1

Answer:

work = force×displacement

for Jerrin, work = 80×1 joule

= 80 joule

for machine, work =120×0.4 joule

= 48 joule

$effi ciency = \frac{work \: done \: by \: machine}{work \: done \: on \: machine} \times 100$

$efficiency = \frac{48}{80 } \times 100$

efficiency = 60 %