Question

3 litre of an aqueous stock solution was prepared by dissolving 270g of glucose in water. 20 ml of the above solution was pipetted into 100 ml volumetric flask, diluted with water and made up to the mark. calculate the molarity of the new solution obtained​

Answer 1

Answer:

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Answer 2

Answer:

0.1 mol L^-1

Explanation:

molarity of stock solution

m1= nC612O6/V

= wC6 H12O6/M C6H12O6×V

wC6H12O6=270 g

MC6H12O6=180 g mol^ -1

v=3L

M1=?

M1=270/180*3=0.5 mol l^-1

M1V1=M2V2

M1=0.5 MOL l^-1

V1=20 ml

v2=100ml

M2=?

M2=0.5×20÷100=0.1 mol L^-1