3 litres of a gaseous mixture of propane and butane are completely burnt to produce total of 11 litres of carbon dioxide . Determine volume of propane and butane in the mixture
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let no of moles of propane = x and butane =y
2 C4H10 + 13 O2 ⇒ 8 CO2 + 10 H2O.for butane when we take 2ltr of it
2ltr 8ltr
C3H8 + 5O2 ⇒ 3CO2 + 4H2O as no of moles is propotional to volume
1ltr 3ltr
from this 2ltr of butane and 1ltr of propane is burned to get 11ltr of co₂
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