Question

3 moles of A and 4 moles of B are mixed together and allowed to come into equilibrium according to the following reaction.
3A(g) + 4B(g) = 2C(g) +3D(g)
when equilibrium is reached, There is 1 mole of C. The equilibrium constant of the reaction is
1÷4
1÷3
1÷2
1
​Please explain step by step...............

Answer 1

3A + 4 B = 2C + 3 D

at equilibrium

3- 3x 4- 4x 2x 3x

as 2x = 1

x = ½

now equilibrium constant = 6x^2 / (3- 3x) (4-4x) = 6/4 / 3 = 2/4 = ½

hence option C is correct

Answer 2

The equilibrium constant of the reaction is 1:3. In the given reaction, 3A + 4B = 2C +3D.

Therefore, at equilibrium state, we can show it as (3-3x), (4-4x), 2x and 3x.

Hence, we can write it as 2x = 1, or x = 1/2.

Moreover, the equilibrium constant = 6 X ^ 2 / (3-3x) (4-4x) = 6/4 / 3 = 2/4 =1/2.

Hence, either way, we are able to see here that the result comes to 1:2 and therefore, it is the correct answer for this question.