Question

3+root2/2+root3=a+rootb find a and b

Answer 1

Answer:

3+√2/2+√3= a+√b

[3+2√2]÷2+√3= a+√b

[3+2√2]÷2= a+√b-√3

3+2√2= 2a+2√b-2√3

3= 2a+2√b-2√3-2√2

3= a+√b-√3-√2

√3+√2+3= a+√b

√b=√3+√2+3+a

b= (√3+√2+3+a)²

b= 3+2+9+a².

So, b= a²+14

So, b= a²+14and, a= √[ b-14 ] OR upper root b -14.