(3-root6)/(3+2root6)=aroot6-b
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3-√6 / 3+√6 = a√6-b
after rationalisng the LHS
⇒(3-√6)² / 3 = a√6 - b
⇒5-2√6 = a√6-b
⇒a = -2 and b = -5
after rationalisng the LHS
⇒(3-√6)² / 3 = a√6 - b
⇒5-2√6 = a√6-b
⇒a = -2 and b = -5
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