Question

3. solve the pair of equation by Elimination
method.
2x + 7y-11=0; 3x-y-5=0​

Answer 1

Answer:

2x+7y=11 ----------------- 1st equation

3x-y = 5-------------------- 2nd equation

multiply 1st equation by -3

multiply 2nd equation by 2

-6x-21y =-33

6x-2y=10

-23y=-23

y=1

x=2

Step-by-step explanation:

Answer 2

The values of x and y are 2 and 1 respectively.

Given:

Two equations: 2x + 7y-11=0 and 3x-y-5=0.

To Find:

The values of ‘x’ and ‘y’ using the method of elimination.

Solution:

In the method of elimination, find out the values of the variables by modifying the equations and suitably adding or subtracting them.

We have been given two equations

2x + 7y-11=0     …………………………….(I)

3x-y-5=0            …...……………………….(II)

Multiplying equation (II) by 7, we get

21x-7y-35=0       ………………………….(III)

Adding equations (I) and (III) we get

(2x + 7y-11)+( 21x-7y-35)=0

23x-46=0

x = 2.

On multiplying equation (I) by 3 and equation (II) by 2, we get:

6x+21y-33=0   ……………………(IV)

6x-2y-10=0      ……………………(V)

Subtracting equation (V) from (IV) we get:

(6x+21y-33) - (6x-2y-10)=0

21y+2y-23 = 0

23y = 23

y = 1.

The values of x and y are 2 and 1 respectively.

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