Question

3 tanx +cotx =5 cosecx

Answer 1

3 tan x + cot x = 5cosec x 


3sin² x + cos²x / cos x . sin x = 5cosθ

3 - 3 cos²x + cos²x /3-2cos²x = 5cos x

2cos² x + 5 cos x -  3 = 0 

2 cos ² x + -cos x -3 = 0 

2 cos x  (cos x + 3 ) - 1 (cos x + 3 ) = 0 

(2 cos x -1 ) = 0 , (cos x + 3) = 0 

cos x = 1/2 and cos x = -3 

cos x = 1/2 

x = 60°

x =   π/3

Answer 2

Refer to the attatched photo for detailed solution.

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