(3) Three tankers contain 403 litres, 434 litres and 465 litres of diesel respectively.
Find the maximum capacity of a container that can measure the diesel of the three
containers exact number of times.
Pls. use the Long division method for HCF
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Answers
Answer:
this question answer is minimum capacity of container is 444 litre
Answer:
how to do -Step 1: Divide the largest number by the smallest number. Step 2: Take divisor as new dividend and remainder as the new divisor, i.e. divide the first divisor by the first remainder. Step 3: Proceed till the remainder is zero and the last divisor will be the HCF of the given numbers.
Step-by-step explanation:
To find the maximum capacity of a container that can measure the diesel of the three containers an exact number of times, we need to find the highest common factor (HCF) of the capacities of the three containers.
Here's how to use the long division method to find the HCF:
Step 1: Write the given numbers in a vertical column.
Step 2: Find the remainder when the largest number is divided by the smallest number.
Step 3: Write the divisor (403) and the remainder (62) as the next row, and divide the divisor by the remainder.
Step 4: Repeat step 3 with the previous remainder (62) and the current remainder (31).
Step 5: The HCF is the last non-zero remainder, which is 31.
Therefore, the maximum capacity of a container that can measure the diesel of the three containers exact number of times is 31 litres.