Question

a receive kar has a uniform acceleration of 8 m S2. what distance will it cover 12 seconds after the start . ​

Answer 1

Answer:

Explanation:

Given:  

Initial velocity is: u=0

Acceleration is: a=4 ms  

2

 

Time is: t=10 s

Using second equation of motion:

s=ut+  

2

1

​  

at  

2

 

s=0×10+  

2

1

​  

×4×10  

2

 

  =0+200=200 m