Question

3 times a number is equal to two times of the other. find the ratio of 3 times the sum and 5 times the difference of two numbers ​

Answer 1

Answer:

LET THE NUMBER BE X , ANOTHER NO. BE Y

3X=2Y (ATQ)

X=2Y/3

==>3(Y+X)/5(Y-X)

==>3(Y+2Y/3)/5(Y-2Y/3)

==>3×5Y/3 / 5×Y/3

==>5Y/5Y/3

==>3/1

RATIO = 3:1

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Answer 2

Answer :

Ratio = 3:1

Step-by-step explanation :

Let a number be x and other number be y.

Three times a number is equal to two times the other.

According to question,

$\implies\:\sf{3x\:=\:2y}$

$\implies\:\sf{x\:=\:\frac{2y}{3}}$

Ratio of 3 times the sum and 5 times the difference of two numbers.

According to question,

$\implies\:\sf{\dfrac{3(x+y)}{5(x-y)}}$

Substitute value of x = 2y/3

$\implies\:\sf{\dfrac{3( \frac{2y}{3} +y)}{5( \frac{2y}{3} -y)}}$

$\implies\:\sf{\dfrac{3( \frac{2y + 3y}{3} )}{5( \frac{2y - 3y}{3})}}$

$\implies\:\sf{\dfrac{3( \frac{5y}{ \cancel3} )}{5( \frac{y}{ \cancel3})}}$

$\implies\:\sf{\cancel\dfrac{15y}{5y}}$

$\implies\:\sf{\dfrac{3}{1}}$

Therefore,

Ratio of the numbers is 3:1