Question

3 to the power minus 6 by 7 into 4 to the power minus 3 by 7 into 9 to the power 3 by 7 into 2 ^ 6 by 7 / 4 + 1 + 1 by 4

Answer 1

Given :   $\dfrac{3^{\frac{-6}{7}}.4^{\frac{-3}{7}}.9^{\frac{3}{7}}.2^{\frac{6}{7}}}{4} + 1 + \dfrac{1}{4}$

3 to the power minus 6 by 7 into 4 to the power minus 3 by 7 into 9 to the power 3 by 7 into 2 ^ 6 by 7 / 4 + 1 + 1 by 4

To Find : Simplify

Solution:

$\dfrac{3^{\frac{-6}{7}}.4^{\frac{-3}{7}}.9^{\frac{3}{7}}.2^{\frac{6}{7}}}{4} + 1 + \dfrac{1}{4}$

4 = 2²   , 9 = 3²

(xᵃ)ᵇ = xᵃᵇ

xᵃ.xᵇ = xᵃ⁺ᵇ

$\dfrac{3^{\frac{-6}{7}}.(2^2)^{\frac{-3}{7}}.(3^2)^{\frac{3}{7}}.2^{\frac{6}{7}}}{4} + 1 + \dfrac{1}{4}$

$\dfrac{3^{\frac{-6}{7}}.2^{\frac{-6}{7}}.3^{\frac{6}{7}}.2^{\frac{6}{7}}}{4} + 1 + \dfrac{1}{4}$

$\dfrac{3^{(\frac{-6}{7} +\frac{6}{7})}.2^{(\frac{-6}{7} + \frac{6}{7})}}{4} + 1 + \dfrac{1}{4}$

$\dfrac{3^{0}.2^{0}}{4} + 1 + \dfrac{1}{4}$

1/4  + 1 + 1/4

= 6/4

= 3/2

$\dfrac{3^{\frac{-6}{7}}.4^{\frac{-3}{7}}.9^{\frac{3}{7}}.2^{\frac{6}{7}}}{4} + 1 + \dfrac{1}{4} =\dfrac{3}{2}$  

Learn more:

By what number should minus 2 upon 3 raise to the power 3 be ...

brainly.in/question/9546305

SIMPLIFY:(6x²-5)-{(4x²+3)+(2x²-8)}

brainly.in/question/8308194

Answer 2

1/21/4 = 4/21 hope it helps you