Math, asked by 11manjuapril, 1 month ago

√3 x^2-2√2x-2√3=0.... solve for x....​

Answers

Answered by vaishubh1707
7

Answer:

x = -√2/√3 or x =✓6

Step-by-step explanation:

√3x²-2√2x -2√3 = 0

√3x²-3√2x+√2x -2√3 = 0

√3x (x-√6)+ √2(x-√6)= 0

(√3x+√2) (x-√6)= 0

√3x+√2 = 0 or x-√6 = 0

√3x= -√2or x = √6

x = -√2/√3 or x =✓6

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