Question

3
x + 7 = 10 has the solution
x-0=
3
: when 3x = 12.
x - l=
: when 2x = 2.
х
15; when
= 6
X-
2​

Answer 1

$\orange{ \underline \bold{:3x + 7 = 10 }} \: \\ \pink{ \underline \bold{:now \: the \: all \: question }} \: \\ \\ \orange{ \underline \bold{:solution............... }} \\ \orange{ \underline \bold{:rule \: of \: bodmas }} \: \: \\ \orange{ \underline \bold{: 3x + 4 - 1x + + 1x + 16}} \: \\ \orange{ \underline \bold{: 7x - 1x + 16x}} \: \\ \orange{ \underline \bold{:6 {x}^{2} + 16x}} \: \\ \orange{ \underline \bold{:6 \times 2 + 16x }} \: \\ \orange{ \underline \bold{:12 + 16x }} \: \\ \orange{ \underline \bold{: 28 \: \: answer}} \: \\ itz \: shiwam..........$