Question

3 years back average age
of A and B was 32. Today
average age of A,B and C is
30. What is the age of C?*​

Answer 1

Answer:

20

Step-by-step explanation:

average age of A and B three years ago = 32

$\frac{(a - 3) + (b - 3)}{2} = 32 \\ a - 3 + b - 3 = 64 \\ a + b - 6 = 64 \\ a + b = 70$

average age of A B and C at present = 30

$\frac{a + b + c}{3} = 30 \\ a + b + c = 90 \\ 70 + c = 90 \\ c = 90 - 70 \\ c = 20$

therefore age of C is 20

Answer 2

The age of C is 30 years.

Step-by-step explanation:

3 years back average age  of A and B was 32.

So, it becomes,

$\dfrac{A+3+B+3}{2}=32\\\\A+B+6=64\\\\A+B=64-4\\\\A+B=60$

Average age of A, B and C = 30 years.

So, it becomes,

$\dfrac{A+B+C}{3}=30\\\\A+B+C=30\times 3=90\\\\60+C=90\\\\C=90-60\\\\C=30\ years$

Hence, the age of C is 30 years.

# learn more:

Sum of present ages of manish and savita is 31 manish age 3 yearsago was 4 times the age of savita find present age

https://brainly.in/question/3430485