Question

30 children at a camp have provisions for 18 days. They are joined by 5 more children how long will the
provisions last?
​

Answer 1

30 children =18days
Then,30+5=35
35=days be x
35*18 =30x
630=30x
X=630^30
=21 days

Answer 2

When 5 more children are joined then the provision last for $15\frac{3}{7}$days

Step-by-step explanation:

Let x be the number of children and y be the number of days of provisions

When number of children increases then number of days of provision decreases.

Therefore, it is inverse proportion.

Therefore, $xy=Constant$

$x_1=30,y_1=18,x_2=30+5=35,y_2=y$

$x_1y_1=x_2y_2$

$30\times 18=35\times y$

$y=\frac{30\times 18}{35}=15\frac{3}{7}$

Hence, when 5 more children are joined then the provision last for $15\frac{3}{7}$days

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