30(n-4)-4(n+8)+10(n+2)=0
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Answered by
2
30(n-4)-4(n+8)+10(n+2)=0
30n-120-4n-32+10n+20=0
36n-152+20=0
36n-132=0
36n=132
n=132/36
n=22/6
30n-120-4n-32+10n+20=0
36n-152+20=0
36n-132=0
36n=132
n=132/36
n=22/6
Answered by
6
According to given sum,
30 (n-4)-4 (n+8)+10 (n+2)=0
=> 30n-120-4n-32+10n+20=0
=> 36n-132=0
=> 36n=132
=> n=132/36
=> n=11/3.
:-)Hope it helps u.
30 (n-4)-4 (n+8)+10 (n+2)=0
=> 30n-120-4n-32+10n+20=0
=> 36n-132=0
=> 36n=132
=> n=132/36
=> n=11/3.
:-)Hope it helps u.
AnkuSingh:
you are Brainlist
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