30 N of force is needed to increase the velocity of a body of mass 5 kg from to 10ms–¹ to 22ms-¹
for the time duration of ……… . (2s, 6s, 12s)
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Given:-
- Force ,F = 30 N
- Mass ,m = 5kg
- Initial velocity,u = 10m/s
- Final velocity ,v = 22m/s
To Find:-
- Time taken ,t
Solution:-
As we know that force is the product of mass and acceleration.
Firstly we calculate the acceleration of the body
• F = m×a
Substitute the value we get
→ 30 = 5×a
→ a = 30/5
→ a = 6m/s²
Therefore the acceleration of the body is 6m/s²
Now , Acceleration is the rate of change of velocity at per unit time
• a = v-u/t
Substitute the value we get
→ 6m/s = 22-10/t
→ 6 = 12/t
→ 6 ×t = 12
→ t = 12/6
→ t = 2s
Therefore the time taken by the car is 2 second.
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