Math, asked by DhruvBose29, 1 year ago

--+--+--+--+-- =30.Solve the puzzle with the numbers(1,3,5,7,9,11,13,15).Numbers can be repeated.Only addition operation allowed.

Answers

Answered by kvnmurty
1
Gaurav Agrawal answered very intelligently and using his imagination.         -- really for this question is asked so many times.. all credit goes to him. 
                           3! + 3! + 3! + 3! + 3!      = 30 

You can answer this question in many ways using the factorial function.  The following are my answers, taking the tip from his answer.

   3! + 1 + 3 + 9 + 11          = 30
       1 + 5 + 7 + 3! + 11               = 30
             3! + 3! + 3! + 11 + 1             = 30
                 3! + 3! + 11 + 5 + 1               = 30
            11+ 1 + 1 + 3! + 11              = 30
       15 + 3 + 3 + 3 + 3!              = 30
     13 + 1 + 1 + 9 + 3!            = 30
         13 + 1 + 3 + 7 + 3!            = 30
               13 + 5 + 3 + 3 + 3!            = 30

If  one can use /, * , exponent and other operators, then you can get more answers too.  Question does not say anything about the operators.

  5 * 3 + 13 + 1 + 1 = 30
     13 + 15 + 3! - 3 - 1 =    30
          15! / 13! / 7 + 1 - 1  =  30
               5!  / 3!  + 1 * 3 + 7 = 30
                      7 * 5  - 3 - 1 - 1  =  30
                   9 * 7 / 3 + 9 * 1 =  30
          3³ + 1 + 11 - 13 * 1  = 30
     5³ / 15 * 3 + 5 * 1 = 30  
 3 * 15 - 11 - 3 - 1 = 30

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You need one operator for which the result is an even number with an input being an odd number.  Factorial is one.  Probably there are other operators too.

Answered by GowriShankar
0
3!+3!+3!+3!+3!=30

Note that 3!=3*2*1=6
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