Question

303+p divided by 41+p

Answer 1

Answer:

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Step-by-step explanation:

Let the number be x

Let the number be xGiven:

Let the number be xGiven: x is added to twice its x

Let the number be xGiven: x is added to twice its x 2

Let the number be xGiven: x is added to twice its x 2 which gives 21.

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0⟹x=3,−

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0⟹x=3,− 2

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0⟹x=3,− 27

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0⟹x=3,− 27The number is 3,−

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0⟹x=3,− 27The number is 3,− 2

Let the number be xGiven: x is added to twice its x 2 which gives 21.2x 2 +x=21⟹2x 2 +x−21=0⟹2x 2 +7x−6x−21=0⟹x(2x+7)−3(2x+7)=0⟹(x−3)(2x+7)=0⟹x=3,− 27The number is 3,− 27