Question

31. If f(x) =(x^2-4÷x^2)
then f(2) is
(a) 0
(b) 2
(c) 4
(d) 1​

Answer 1

Answer:

According to question f (x) ={(x^2-4)/(x-2)}

Now if you see the function f(x) you will say that at x=2 functional value is not defined so inorder to make the function defined at x=2 it is given that f (2) = 3.

But if you check the limiting value of the function you will find that

lim x→2 f (x) = {(x^2-4)/(x-2)}

={(x-2)(x+2)/(x-2)} = (x+2) = (2+2)=4

So the limiting value of the function at x=2 is 4 but the functional value at x=2 is 3.