Question

32. (2x + 3y + z)^2-(2x - 3y + z)^2 = ?
the answer is 24xy+12yz
but how pls solve my question pls​

Answer 1

Answer:

Done below-

Step-by-step explanation:

Bro, if you don't mind, then mark the answer as $brainliest$ if it helps you

So, let's begin!

$(2x+3y+z)^2-(2x-3y+z)^2\\= [\;\;(2x)^2+(3y)^2+(z)^2+2(2x)(3y)+2(3y)(z)+2(z)(2x)\;\;]-[\;\;(2x)^2+(-3y)^2\\\\+(z)^2+2(2x)(-3y)+2(-3y)(z)+2(z)(2x)\;\;]\\\\=[4x^2+9y^2+z^2+12xy+6yz+4zx]-[4x^2+9y^2+z^2-12xy-6yz+4zx] \\\\\\=4x^2+9y^2+z^2+12xy+6yz+2zx-4x^2-9y^2-z^2+12xy+6yz-4zx \\\\=24xy+12yz\\\\Hecnce\;\;proved\\\\\\Learning\;\;together\;:)$