Question

32. The angles of a triangle are in AP. The greatest angle is twice the least. Find all the
angles of the triangle
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Answer 1

Step-by-step explanation:

Let a - d, a, a + d be the three angles of the triangle that form AP.

Given that the greatest angle is twice the least. Now,

{ 2(a - d) }= {a + d 2a - 2d} = {a + d}

= a = 3d ---------------(1) Now by angle sum property,

(a - d) + a + (a + d) = 180°

3a = 180°

a = 60°----------------------(2)

from (1) and (2),

3d = 60° d = 20°

Now, the angles are,

a - d = 60°- 20° = 40°

a = 60°

a + d = 60° + 20° = 80°.

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Answer 2

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